Question

Draw triangle ABC such that BC = 5 cm, ∠ABC = 60°. ∠ACB = 30º. Now construct ΔA'BC' corresponds to ΔABC with A'B : AB = 3 : 2.

Answer 1

Steps of construction :

1. Draw a line segment BC of length 5 cm.

2. Draw the angles of 60° and 30º on the points B and C respectively. which intersect each other at A.

3. ΔABC is the given triangle.

4. Draw a ray BX making an acute angle with BC.

5. Locate three points B₁,B₂, and B₃ on line segment BX. Such that BB₁ = B₁B₂ = B₂B₃.

6. Join B₂C.

7. Draw B₃C' || B₂C  to intersect the extended line BC' at C'.

8. Through C draw a line parallel to AC intersecting extended line segment BA at A'.

ΔA'BC' is the required triangle.