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in Chemistry by (91.1k points)
HBr reacts with `H_(2)C=CH-OCH_(3)` under anhydrous conditions at room temperature to give:
A. `CH_(3)CHO` and `CH_(3)Br`
B. `BrCH_(2)CHO` and `CH_(3)OH`
C. `BrCH_(2)-CH_(2)-OCH_(3)`
D. `H_(3)C-CHBr-OCH_(3)`

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