Question

For a Cannizzaro reaction
`R - CHO + NaOH rarr`
Rate law is derived as : `Rate = k [RCHO]^(2) [HO}^(2)`
from the above rate law, it can be concluded that
A. hydride donor is a dianion
B. reaction involved hydride ion transfer
C. reaction does not show kinetic isotopic effect
D. reaction is pseudo `2^(nd)` order

Answer 1

Correct Answer - A
For formation of dianion hydride donor, an additional mole of `NaOH` is sonsument.

Hence, rate become `2^(nd)` order with respect to `HO` and fourth order overall.