Question

The sketech below show cross secion so equipotential surfaces between two charged.Conductors that are shwon in solid black.Some points on the wquipotenital surfaces .near the conductors are marked as `A,B,C…. .` The arrangements lies in air (Take `epsilon_(0)=8.85xx10^(-12)C^(2)//Nm^(2)]`

Surfaces charge density of the plate is equal to
A. `8.85xx10^(-10)C//m^(2)`
B. `-8.85xx10^(-10)C//m^(2)`
C. `17.7xx10^(-10)C//m^(-2)`
D. `-17.7xx10^(-10)C//m(2)`

Answer 1

Correct Answer - A
`E=(40-10)/(0.3)=100V//m`
(near the plate the electric field has to be uniform it is alomost due to the particle
For conducting plate
`E=(sigma)/(epsilon_(0))sigma=epsilon_(0)E`
therefore `s=8.85xx10^(-12)xx100`
`=8.85xx10^(-10)C//m^(2)`