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The sketch below show cross section so equipotential surfaces between two charged.Conductors that are shown in solid black.Some points on the equipotenital surfaces .near the conductors are marked as `A,B,C…. .` The arrangements lies in air (Take `epsilon_(0)=8.85xx10^(-12)C^(2)//Nm^(2)]`
image
Surfaces charge density of the plate is equal to
A. `2xx10^(-5)J`
B. `-2xx10^(-5)J`
C. `4xx10^(-5)J`
D. `-4xx10^(-5)J`

1 Answer

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Best answer
Correct Answer - D
`W=q.DeltaV`
`=-1xx10^(-6)[20-(-20)]`
`=-4xx10^(-5)J`

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