Question

The molal boiling point constant of water is `0.573^(@)C kg "mole"^(-1)`. When `0.1` mole of glucose is dissolved in `1000g` of water, the solution boils under atmospheric pressure at:
A. `100.513^(@)C`
B. `100.0573^(@)C`
C. `100.256^(@)C`
D. `101.025^(@)C`

Answer 1

Correct Answer - B
`T - 100 = 0.573 xx 0.1`
`T = 100.0573`