Question

`P(g)+2Q(g)toPQ_(2)(g),DeltaH=18kJmol^(-1)`
The entropy change of the above reaction `(DeltaS_("system")` is 60 `JK^(-1)mol^(-1))`. At what temperature the reaction becomes spontaneous?
A. Below 200 K
B. Above 300 K
C. Below 300 K
D. Above 200 K and below 300 K.

Answer 1

Correct Answer - B
For spontaneous process `DeltaGlt0`
`thereforeDeltaH-TDeltaSlt0,DeltaHltTDeltaS`
`thereforeTgt(DeltaH)/(DeltaS)=(18000)/(60)=300K`