Question

Binding energy per nucleon of fixed nucleus `X^(A)` is `6 MeV`. It absorbs a neutron moving with `KE= 2 MeV` and converts into Y at ground state, emitting a photon of energy `1 MeV`. The Binding energy per nucleon of Y (in MeV) is -
A. `((6A+1))/((A+1))`
B. `((6A-1))/((A+1))`
C. 7
D. can not be determined

Answer 1

Correct Answer - B
BE of X = 6A
BE of `Y = 6A - 2 + 1 = 6A - 1`
[Because absorption of energy decreases BE and releas of energy increase BE]
In Y nuclues there are A + 1 nuclues
`:. (BE)/("nucleon") = (6A -1)/(A+1)`.