Question

Binding energy per nucleon of fixed nucleus `X^(A)` is `6 MeV`. It absorbs a neutron moving with `KE= 2 MeV` and converts into Y at ground state, emitting a photon of energy `1 MeV`. The Binding energy per nucleon of Y (in MeV) is -
A. `((6A+1))/((A+1))`
B. `((6A-1))/((A+1))`
C. `7`
D. `(7)/(6)`

Answer 1

Correct Answer - B
`BE` of `X=6A`
`BE` of `Y=6A-2+1=6A-1`
[Because absorption of energy decreases `BE` and releas of energy increases `BE`]
`:. (BE)/("nucleon")=(6A-1)/(A+1)`