Correct Answer - A::D
`underset((0.1)/(2))(A(g))tounderset(0)(B(g))+underset(0)(2C(g))`
`t=250sec`
`t_((1)/(2))=(0.693)/(2.772xx10^(-3))=250sec`
Hence after 250 sec.
`[A]=(0.1)/(2xx2)=0.025M,[C]=2xx(0.1)/(2xx2)=(0.1)/(2)M=0.05M`
`impliesP_(C)=(0.1)/(2)xx0.082xx300=1.23atm`.