Correct Answer - `3`
`P_(1) = sqrt(2m(100 eV))`
`lambda_(P) = (h)/(sqrt(2m(100eV))) rArr lambda_(alpha)=(h)/(sqrt(2(4m)2(100 eV)))`
`lambda_(P)/lambda_(alpha)=sqrt(8)`
rArr The ratio `lambda_(p)/lambda_(alpha)`, to the nearest integer, is equal to `3`.