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An `alpha`- particle and a proton are accelerated from rest by a potential difference of `100 V` After this their de Broglie wavelength are `lambda_(a

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An `alpha`- particle and a proton are accelerated from rest by a potential difference of `100 V` After this their de Broglie wavelength are `lambda_(a) and lambda_(p)` respectively The ratio `(lambda_(p))/ lambda_(p)` , to the nearest integer is
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Correct Answer - `3`
`h/lambda=p=sqrt(2mqV)`
`implies lambda_(P)/lambda_(alpha)=sqrt((m_(alpha)q_(alpha))/(m_(P)q_(P)))=sqrt(4xx2)=sqrt(8)~~3`
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