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`1 "मिमी"^2` परिच्छेद क्षेत्रफल में `5xx10^(19)` इलेक्ट्रान प्रति सेकण्ड अभिलंबवत गुजर रहे है। परिच्छेद में प्रवाहित धारा तथा धारा घनत्व ज्ञात कीजिए ।

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परिच्छेद से प्रति सेकण्ड प्रवाहित आवेश
q=ne=`(5xx10^(19))(1.6xx10^(-19))=8`कुलाम
विधुत धारा `I=q/t=8/1=8` ऐम्पियर
धारा घनत्व `J=I/S=8/(1xx10^(-6))=8xx10^6 "ऐम्पियर/मीटर"^2`

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