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ताम्बे के तर 50 मीटर लम्बे तथा 2 मिमी व्यास वाले तार का प्रतिरोध ज्ञात कीजिये । ताम्बे का विशिष्ट प्रतिरोध `1.7xx10^(-8)` ओम - मीटर है ।

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तार का प्रतिरोध `R=rho(l)/(A)`
प्रश्नानुसार, `rho=1.7xx10^(-8)` ओम - मीटर, l=50 मीटर
`A=pir^2=3.14xx(1xx10^(-3))^2=3.14xx10^(-6) "मीटर"^2`
`R=(1.7xx10^(-8)xx50)/(3.14xx10^(-6))=0.27`ओम

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