माना ` " "y= (log _ex )^(sinx ) `
` rArr log y =sin x log log x `
दोनों पक्षों का x के सापेक्ष अवकलन करने पर
` (1)/(y) (dy)/(dx)=sin x ((1)/(log x )*(1)/(x) )+ log log x *cos x `
` therefore " "(dy)/(dx) =y{(sin x )/(x log x )+cos x*log log x}`
` rArr " "(dy)/(dx) =(log _ex) ^(sinx) [(sin x )/(x*log x)+ cos x* loglog x ]`
