Question

माना `E_(1)" व "E_(2)` स्वतन्त्र घटनाएँ है तथा `P(E_(1))=0.3" तथा "P(E_(2))=0.4` तब निम्न के मान ज्ञात कीजिए-
(i) `P(E_(1)capE_(2))` (ii) `P(E_(1)cupE_(2))`
(iii) `P(E_(1)//E_(2))` (iv) `P(E_(2)//E_(1))`

Answer 1

Correct Answer - (i) 0.12 (ii) 0.58 (iii) 0.3 (iv) 0.4`
(i) `P(E_(1) cap E_(2))=P(E_(1)) cdot P(E_(2))=(3)/(10)xx(4)/(10)=(12)/(100)`