Comparing the equation 5x2 + 2xy – 3y2 = 0
with ax2 + 2hxy + by2 = 0, we get,
a = 5, 2h = 2, b = -3
Let m1 and m2 be the slopes of the lines represented by 5x2 + 2xy – 3y2 = 0

Now required lines are perpendicular to these lines
∴ their slopes are \(\frac{-1}{m_1}\) and \(\frac{-1}{m_2}\)
Since these lines are passing through the origin, their separate equations are
