Comparing the equation xy + y2 = 0 with ax2 + 2hxy + by2 = 0, we get,
a = 0, 2h = 1, b = 1
Let m1 and m2 be the slopes of the lines
represented by xy + y2 = 0

Now required lines are perpendicular to these lines
∴ their slopes are \(\cfrac{-1}{m_1}\) and \(\cfrac{-1}{m_2}\).
Since these lines are passing through the origin, their separate equations are

∴ separate equations of the lines are y = 0 and
3x2 + 8xy + 5y2 = 0.
x + y = 0.
Let m1 and m1 be the slopes of these lines.
Then m1 = 0 and m2 = -1
Let m1 and m2 be the slopes of these lines.
Then m1 = 0 and m2 = -1

Since these lines are passing through the origin, their separate equations are x = 0 and y = x,
i.e. x – y = 0
∴ their combined equation is
x(x – y) = 0
x2 – xy = 0.