Question

Calculate the `EMF` of the cell in which the following reaction takes place `:`
`Ni(s)+2Ag^(o+)(0.002M) rarr Ni^(2+)(0.160M)+2Ag(s)`

Answer 1

Applying nearest equation,
`E_(cell)^(@)=E_(cell)^(@)-(0.0591)/(n)log(([Ni^(2+)])/([Ag^(+)]^(2)))`
`=1.05V-(0.0591)/(2)log((0.160)/((0.002)^(2))`
`=1.05-(0.591)/(2)log(4xx10^(4))`
`=1.05-(0.0591)/(2)(4.6021)`
`=1.05-0.14V`
`=0.91V`