Correct Answer - `xsin^(-1)x+sqrt(1-x^2)`
`I =int sin^(-1)x dx =int sin^(-1)x 1dx`
`=sin^(-1)x int 1 dx -int {d/(dx)(sin^(-1)x)int 1dx}dx`
`=sin^(-1)x.x-int1/sqrt(1-x^2)xdx`
अब ` q-x^2=t^2` रखने पर
`I=x sin^(-1)x - int1/t(-t)dt =x sin^(-1)x +int1 dt`
`=x sin^(-1)x +sqrt(1-x^2)`
