Step-1 : 1 to determine the molecular formula of the compound.
Emperical formula of the given compound `=C_(5)H_(10)O`
Molecular formula `=n xx ` (emperical formula)
Where n`=("Molecular mass of the compound")/("Emperical formula mass of compound")`
Given , molecular mass =86
Emperical formula mass of `C_(5)H_(10)O =(12xx5)+(10xx1)+16=60+16=86`
`n=(86)/(86)=1`
Molecular formula `=1xx(C_(5)H_(10)O)`
`therefore ` Molecular formula `=C_(5)H_(10)O`