Correct Answer - a
Here, `y_(1)=0.05sin (3pit-2x), y_(2)=0.05 sin (3pit+2x)`
According to superposition principle, the resultant
displacements is
`y=y_(1)+y_(2) = 0.05 [sin (3pit-2x)+ sin (3pit+2x)`
or `y= 0.05 xx 2 sin 3pit cos 2x`
or, `y=(0.1 cos 2x) sin 3pit = R sin 3pit`
where,`R= 0.1 cos 2x=` amplitude of the resultant
standing wave.
At `x= 0.5` m
`R=0.1 cos 2x = 0.1 cos 2 xx 0.5`
`= 0.1 cos 1 ("radian") = 0.1 cos frac(180^(@))(pi) = 0.1 cos 57.3^(@)`
or `R=0.1xx054 m = 0.054 m = 5. 4 cm`