Question

Standing waves are produced by the superposition of
two waves
`y_(1)=0.05 sin (3 pit-2x) and y_(2) = 0.05 sin (3pit+2x)`
Where x and y are in metres and t is in second. What
is the amplitude of the particle at `x = 0.5` m ? (Given,
`cos 57. 3 ^(@) = 0. 54)`
A. 2.7 cm
B. 5.4 cm
C. 9.98 cm
D. 0.10 cm

Answer 1

Correct Answer - B
`R=2A cos ((2pix)/(lamda))`
`2xx0.05xxcos((2pixx0.5)/(pi))=0.1xxcos(1)^C`
`0.1cos(57.3)^@=0.1xx0.54=5.4cm`