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A parallel beam of light of wavelength `6000Å` gets diffracted by a single slit of width 0.3 mm. The angular position of the first minima of diffracted light is :
A. `6xx10^(-3)` rad
B. `1.8xx10^(-3)` rad
C. `3xx10^(-3)` rad
D. `2xx10^(-3)` rad

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Best answer
Correct Answer - D
We have d `sin theta =n lambda`
`0.3xx10^(-3) xx theta=6000xx10^(-10)`
The angular position ` theta=2xx10^(-3)` rad

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