Question

Ligth of wavelength `4000 Å` is incident on a metal plate whose work function is `2 eV`. What is maximum kinetic enegy of emitted photoelectron ?
A. 0.5 eV
B. 1.1 eV
C. 1.5 eV
D. 2.0 eV

Answer 1

Correct Answer - B
As maximum `KE=(hc)/(lamda)-phi_(0)`
`=(6.6xx10^(-34)xx3xx10^(8))/(4000xx10^(-10))xx(1)/(1.6xx10^(-19))-2=1.1eV`