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Light of wavelength 4000 Å is incident on a sodium surface for which the threshold wavelength of photoelectrons is 5420 Å. The work function of sodium is
A. 0.57 eV
B. 1.14 eV
C. 2.29 eV
D. 4.58 eV

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Correct Answer - C
As `phi_(0)=(hc)/(elamda_(0))` (in eV)
`=(6.62xx10^(-34)xx3xx10^(8))/(5420xx10^(-10)xx1.6xx10^(-19))=2.29eV`

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