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The equation of a transverse wave travelling in a rope is given by `y = 5 sin (4t - 0.02 x)`, where y and x are in cm and time t is in second. Then th

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The equation of a transverse wave travelling in a rope is given by `y = 5 sin (4t - 0.02 x)`, where y and x are in cm and time t is in second. Then the maximum transverse speed of wave in the rope is
A. 125 cm/s
B. 200 cm/s
C. 250 cm/s
D. 100 cm/s
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1 Answer

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Correct Answer - B
`v = (omega)/(k) = (4)/(0.02) = (400)/(2) = 200`
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