Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
112 views
in Physics by (93.5k points)
closed by
बोर मॉडल के अनुसार सूर्य के चारो ओर `1.5xx10^(11)m` त्रिज्या की कक्षा में `3xx10^(4)m//s` के कक्षीय वेग से परिक्रमा करती पृथ्वी की अभिलाक्षणिक क्वांटम संख्या ज्ञात कीजिए (पृथ्वी का द्रव्यमान `=6.0xx10^(24)kg`)|

1 Answer

0 votes
by (92.5k points)
selected by
 
Best answer
सूर्य के चारो ओर पृथ्वी का कोणीय संवेग
`mvr=(nh)/(2pi)`
`n=(2pimvr)/(h)`
या `=(2xx3.14xx6xx10^(24)xx1.5xx10^(11)xx3xx10^(4))/(6.6xx10^(-34))`
`=2.57xx10^(74)`.

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...