Question

A potential difference of `0.75V` applied across a galvanometer causes a current of 15 m A to pass through it. If can be converted into ammeter of range of 25 A , the requried shunt should be
A. `0.3Omega`
B. `0.03Omega`
C. `0.003Omega`
D. `0.0003Omega`

Answer 1

Correct Answer - B
`V_Gi_g G therefore I_g=V_g//G = 5xx10^-4A`
`S=((I_g)/(I-I_g))G=((5xx10^-4)/(5-0.0005))xx100=0.01Omega`