Question

A galvanometer having a resistance of 20 ohm and capable of carrying a maximum current of 40 m A is to be converted into an ammeter of range `0-5` A. What is the resistance needed?
A. `1.6Omega` in parallel
B. `0.16Omega` in parallel
C. `16.1Omega` in parallel
D. None of these

Answer 1

Correct Answer - B
`S=(I_g .G)/(I-I_g)`
`S=(40xx10^-3xx20)/(5-0.040)=0.16Omega` .