Question

A transformer has `100` turns in the primary coil and carries `8A` current. If input power is one kilowatt, the number of turns required in the secondary coil to have `500V` output will be
A. 100
B. 200
C. 400
D. 300

Answer 1

Correct Answer - C
`P_(P)=I_(P)*e_(P)`
`e_(P)=(P_(P))/(I_(P))=(1xx10^(3))/(8)`
`n_(S)=(e_(S))/(e_(P))xxn_(P)=(500xx100xx8)/(1000)=400`