Question

An ac source of frequency 50 Hz is connected with a resistance `(R=36Omega)` and L of 0.12 H in series. What is the phase different between current and voltage?

Answer 1

IF `theta` be the phase difference, then
`tantheta=(omegaL)/R`
or,`theta=tan^-1""(omegaL)/R=tan^-1"(314times0.12)/36=tan^-1(1.047)=46.3^@`
[here `omega=2pitimes50=2times3.14times50=314 Hz`]
So, phase difference =`46.3^@`.