Question

Formation of polyethylene from calcium carbide takes place as follows
`CaC_(2)+2 H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)`
`C_(2)H_(2)+H_(2) rarr C_(2)H_(2)`
`N(C_(2)H_(4)) rarr (-CH_(2)-CH_(2)-)_(n)`
The amount of polyethylene obtained from `64.1 kg CaC_(2) ` is
A. 7kg
B. 14kg
C. 21kg
D. 28kg

Answer 1

Correct Answer - D
64kg of `CaC_(2)` produces ethylene=28kg
Amount of polythene produced=28kg