Quantity of charge passed (Q) `= "Current in amperes" xx"Time in seconds"`
`=(0.015 A)xx(15xx60)s=13.5 A s=13.5 C`
Gram equivalent mass of zinc`=(65.4)/(2)=32.7`
Now, `" " 96500" C"` of charge deposit zinc =32.7 g
13.5 C charge will deposit zinc `=((32.7 g))/((96500 C))xx(13.5 C)=4.57xx10^(-3) g`