Question

A 5 ampere current is passed through a solution of zinc sulphate for 40 minutes. The amount of zinc deposited at the cathode is

(a) 0.4065 g

(b) 65.04 g

(c) 40.65 g

(d) 4.065 g

Answer 1

Correct option (d) 4.065 g

Explanation :

Current (I) = 5 ampere and time (t) = 40 minutes = 2400 seconds. Amount of electricity passed (Q) = I x t = 5 x 2400 = 12000 C

Since two charges (i.e. 2 x 96500 C) deposits 65.39 gm of zinc, therefore 12000 C will deposit