Question

Calculte molar conductance at infinite dilution for acetic acid, given
`A_(m)^(oo)HCI=425 ohm^(-1)cm^(-1),A_(m)^(oo)NaCI=188 ohm^(-1)cm^(-1),A_(m)^(oo)CH_(3)COOHNa=96 ohm^(-1)cm^(-2)mol^(-1)`

Answer 1

Correct Answer - `333 ohm^(-1)cm^(2)mol^(-1)`
`Lambda_(m(CH_(3)COOH))^(oo)=Lambda_(m(CH_(3)COONa))^(oo)+Lambda_(m(HCl))^(oo)-Lambda_(m(NaCl))^(oo)`
`=(96.0+425.0-188.0)" ohm"^(-1)cm^(2)mol^(-1)=333" ohm"^(-1)cm^(2)mol^(-1)`.