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When `0.1 mol MnO_(4)^(2-)` is oxidized the quantity of electricity required to completely oxidize `MnO_(4)^(2-)` to `MnO_(4)^(-)` is
A. `2xx96500 C`
B. `9650" C "`
C. `96.50" C "`
D. `96500"C"`

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Correct Answer - B
(b) `underset(1" mol")(MnO_(4))^(-) to (MnO_(4))^(-)+underset(1F)e^(-)`
Electricity needed to oxidise 1 mole of `MnO_(4)^(-)` ions =1F.
Electricity needed to oxidise 0.1 mole of `MnO_(4)^(-)` ions =0.1 F =9650 C

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