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Silver atom has completely filled `d` orbitals `(4d^(10))` in its ground state. How can you say it is a transition element?

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The configuration of silver is `[Kr]4d^(10)5s^(1)`. It acquires `4d^(10)` configuration by losing `5s^(1)` electron. Moreover, the last electon is filled in the 4d sub-shell. Threfore , the element is regarded as a transition metals.

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