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Find the point on the curve y = x^3 - 11x + 5 at which the equation of tangent is y = x - 11.

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Find the point on the curve y = x3 - 11x + 5 at which the equation of tangent is y = x - 11.

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Slope of the tangent y = x - 11 is 1,

y = x3 - 11x + 5

Since (-2, 19) does not lie on the tangent y = x - 11

.. .  Requred point is (2, -9).

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