Question

From some instruments current measured is `I=10.0amp`, potential different measured is `V=100.0 V`, length of wire is `31.4 cm`, and diameter of wire is `2.00mm` (all in correct significant figure). The resistivity of wire (in correct significant figures)will be (use `pi=3.14`)
A. `1.00 xx 10^(-4) Omega-m`
B. `1.00 xx 10^(-4) Omega-m`
C. `1.00 xx 10^(-4) Omega-m`
D. `1.00 xx 10^(-4) Omega-m`

Answer 1

`rho=(piD^(2))/(4L)=(V)/(L)=((3.14)(2.00xx10^(-3))^(2))/(4(0314))((100.0)/(10.0))`
and answer should be in three `S.F` so `rho = 1.00 xx 10^(-4)Omega -m` .