Question

How much glucose, `C_(6)H_(12)O_(6)` must be dissolved per litre of the solution that yields osmotic pressure os 2.72 atmospheres at 298 K ? R=0.0821 L atm `K^(-1)`.

Answer 1

Correct Answer - 20.016 g
`"Molar mass of glucose "C_(6)H_(12)O_(6), M_(B)=6xx12+12+6xx16=180" g mol"^(-1)`
`V=1.0L, pi=2.72 atm, R=0.0821" L atm K"^(-1)mol^(-1), T=298K, W_(B)=?`
`piV=n_(B)RT or n_(B)=(piV)/(RT),W_(B)/M_(B)=(piV)/(RT)`
`W_(B)=(M_(B)xxpixxV)/(RT)=((180" g mol"^(-1))xx(2.72" atm")xx(1L))/((0.0821"L atm K"^(-1)mol^(-1))xx(298 K))=20.0116 g.`