Question

In the nth orbit, the energy of an electron `E_(n)= -( 13.6)/(n^(2)) eV` for hydrogen atom. The energy rquired to take the electron from first orbit to second orbit will be
A. `10. 2 eV`
B. `12.1 eV`
C. `13.6 eV`
D. `3.4 eV`

Answer 1

Correct Answer - A
For n=2, using, `E_(n)=(-13.6eV)/(n^(2))E_(2)=-(13.6)/((2)^(2))=-3.4 eV`
For n=1,`E_(1)=-13.6 eV`
`:. " " E_(1rarr2)=-3.4-(-13.6)=10.2ev`