IN a nuclear reactor, fission is produced in 1 g of `.^(235)U`
`(235.0349 am u)`. In assuming that `._(53)^(92)Kr (91.8673 am u)`
and `._(36)^(141)Ba (140.9139 am u)` are produced in all reactions and no energy is lost, calculate the total energy produced in killowatt. Given: `1 am u =931 MeV`.