Correct option is (A) (2, 2)
\(\because\) \(log_2\,8=log_2\,2^3\)
\(=3\,log_2\,2=3\) \((\because log_a\,a=1)\)
\(log_5\,25=log_5\,5^2\)
\(=2\,log_5\,5=2\)
\(log_{10}\,10=1\)
and \(log_{10}\,100=log_{10}\,10^2\)
\(=2\,log_{10}\,10=2\)
\(\therefore\) \(A=(log_2\,8,log_5\,25)=(3,2)\)
& \(B=(log_{10}\,10,log_{10}\,100)=(1,2)\)
\(\therefore\) Mid-point of AB is mid-point of (3, 2) & (1, 2)
\(=(\frac{3+1}2,\frac{2+2}2)\)
\(=(\frac{4}2,\frac{4}2)=(2,2)\)