Question

Consider the reaction:
`N_(2(g))+3H_(2(g))rarr 2NH_(3(g))`.
The equally relationship between `-(d[NH_(3)])/(dt)` and `-(d[H_(2)])/(dt)` is:
A. `(d[NH_(3)])/(dt)=-(1)/(3)(d[H_(2)])/(dt)`
B. `+(d[NH_(3)])/(dt)=-(2)/(3)(d[H_(2)])/(dt)`
C. `+(d[NH_(3)])/(dt)=-(3)/(2)(d[H_(2)])/(dt)`
D. `(d[NH_(3)])/(dt)=-(d[H_(2)])/(dt)`

Answer 1

`-(1)/(3)(d[H_(2)])/(dt)=+(1)/(2)(d[NH_(3)])/(dt)`