Question

in a reacton, of acidified hydrogen peroxide with potassium iodide, the concentration of iodine formed rises from 0 to `10^(-5) "mil dm"^(-3)` in 10 seconds. What is the rate of reaction ?
A. `10^(-6)"mol dm"^(-3)s^(-1)`
B. `10^(6)"mol dm"^(-3)s^(-1)`
C. `10^(-5)"mol dm"^(-3)s^(-1)`
D. `10^(4)"mol dm"^(-3)s^(-1)`

Answer 1

The reaction is
`2I^(-)+H_(2)O_(2)+2H^(+)rarrI_(2)+2H_(2)O`
`"Rate"=+(d[I_(2)])/(dt)=(10^(-5))/(10)=10^(-6) "mol dm"^(-3)s^(-1)`