Correct Answer - B
Weight of gas =0.24g
Volume of gas (V) -45 mL -0.45 L
Density of `H_(2)`(d) =0.089
Weight of 45 mL of `H_(2)=Vxxd=0.045xx0.089`
`4.005xx10^(-3)` g
Therefore , vapour density
`=("Weight of certain volume of substance")/("Weight of same volume of hydrogen")`
`=(024)/(4.005xx10^(-3))=59.93`