Question

If 0.24 g of a volatile liquid upon vaporization gives 45 ml of vapours at NTP.What will be the vapour density of the substance ? (Density of `H_(2) =0.089 gL^(-1))`
A. `95.39`
B. `5.993`
C. `95.93`
D. `56.0`

Answer 1

Correct Answer - D
45 mL of vapours at NTP weight =0.24 g
`therefore ` 22400 mL of the vapour at NTP weighs
`(0.24)/(45)xx22400= 112 g `
Thus mol mass = 112
As Mol. Mass =`2xx ` vapour density
`therefore " vapour density " =("Mol.mass" )/(2)=112/2= 56`.