Question

The velocity of a particle is given by `v=(2t^(2)-4t+3)m//s` where t is time in seconds. Find its acceleration at t=2 second.

Answer 1

Acceleration (a) `=(dv)/(dt)=(d)/(dt)(2t^(2)-4t+3)=4t-4`
Therefore acceleration at `t=2s` is equal to, `a=(4xx2)-4=4 m//s^(2)`