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`K_(2)Cr_(2)O_(7)` on heating with aqueous NaOH gives
A. `CrO_(4)^(2-)`
B. `Cr(OH)_(3)`
C. `Cr_(2)O_(7)^(2-)`
D. `Cr(OH)_(2)`

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Best answer
Correct Answer - A
`K_(2)Cr_(2)O_(7) + 2NaOH to K_(2)CrO_(4) to K_(2)CrO_(4) + Na_(2)CrO_(4) + H_(2)O`
Hence, `CrO_(4)^(2-)` ion is obtained.

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